This tutorial provides a reference to all the operators that have been discussed in previous tutorials, showing the different operators in a single place with their precedence and associativity. At the end, practice questions are also provided, so don’t forget to solve them.
| Precedence | Operators | Associativity |
|---|---|---|
| 1st | () | Left to right |
| 2nd | Postfix increment and decrement (++, –) | Left to right |
| 3rd | Unary + and -, Logical negation (!), Prefix increment and decrement (++, –) | Right to left |
| 4th | *, /, % | Left to right |
| 5th | +, – | Left to right |
| 6th | <, <=, >, >= | Left to right |
| 7th | ==, != | Left to right |
| 8th | && | Left to right |
| 9th | || | Left to right |
| 10th | =, +=, -=, *=, /=, %=, <<=, >>=, &=, |=, ^= | Right to left |
| 11th | , (Comma) | Left to right |
Consider the variables a = 5, b = 3, and c = 7. Solve this expression a + b * c - b / a
a + b * c - b / a
= 5 + 3 * 7 - 3 / 5
= 5 + 21 - 0 (integer division)
= 26Consider the variables x = 10, y = 5, and z = 8. Solve this expression x % y + z * x - y
x % y + z * x - y
= 10 % 5 + 8 * 10 - 5
= 0 + 80 - 5
= 75Consider the variables a = 5, b = 3, c = 7, d = 2. Solve this expression result = (a += b) * (c > d) + (++b, --a) && (c <= d)
result = (8) * (c > d) + (++b, --a) && (c <= d)
result = (8) * (1) + (++b, --a) && (c <= d)
result = (8) * (1) + (3, 7) && (c <= d)
result = (8) * (1) + (7) && (c <= d)
result = (8) * (1) + (7) && (0)
result = 8 + (7) && (0)
result = 15 && 0
result = 0Consider the variables p = 15, q = 4, r = 3, s = 2. Solve this expression (p %= q) + (r != s) && (q += r, p -= s) || (r *= q)
(p %= q) + (r != s) && (q += r, p-=s) || (r *= q)
(3) + (r != s) && (q += r, p-=s) || (r *= q) [p = p % q => p = 15 % 4 => p = 3]
(3) + (1) && (q += r, p-=s) || (r *= q) [3 != 2 = True = 1]
(3) + (1) && (7, 1) || (r *= q) [q = 7, p = 3 - 2 = 1]
(3) + (1) && (7, 1) || (21) [r = r * q => r = 3 * 7 = 21]
4 && (7, 1) || (21)
4 && 1 || 21 [(7, 1) = 1]
1 || 21
1Consider the variables m = 6, n = 3, o = 4, p = 2. Solve this expression (m *= n) / (o < p) - (n++, m--, o += p)
(m *= n) / (o < p) - (n++, m--, o += p)
(18) / (o < p) - (n++, m--, o += p) [m = m * n = 6 * 3 = 18]
(18) / (0) - (n++, m--, o += p) [o < p = 4 < 2 = False = 0]
(18) / (0) - (4, 17, 6) [n++ => n = 4, m-- => m = 17, o += p => o = 4 + 2 = 6]
(18) / (0) - (6) [(4, 17, 6) = 6]
undefined [because of division by zero]
Leave a comment